Question Details

Question No: 288

For how many values of $x$ in $[0,\pi]$ is $\sin^{ - 1}(\sin 6x) = \cos^{ - 1}(\cos x)$? Note: The functions $\sin^{ - 1} = \arcsin$ and $\cos^{ - 1} = \arccos$ denote inverse trigonometric functions.

Answer must be a floating-point or integer value and precision error less than 10^-6 is allowed.


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Tags: Algebra Combinatorics