<p>If the arithmetic mean of <img alt="$a$" height="10" src="https://latex.artofproblemsolving.com/c/7/d/c7d457e388298246adb06c587bccd419ea67f7e8.png" width="11" /> and <img alt="$b$" height="14" src="https://latex.artofproblemsolving.com/8/1/3/8136a7ef6a03334a7246df9097e5bcc31ba33fd2.png" width="10" /> is double their geometric mean, with <img alt="$a>b>0$" height="13" src="https://latex.artofproblemsolving.com/f/a/a/faaa8e0ee4c7cc10efb7957393ffcba8ba661bca.png" width="74" />, then a possible value for the ratio <img alt="$a/b$" height="18" src="https://latex.artofproblemsolving.com/e/0/c/e0c22354f6f8870c3a024305aa3afed00b26bcf5.png" width="26" />, to the nearest integer, is:</p>

Question No: 302

If the arithmetic mean of $a$ and $b$ is double their geometric mean, with $a>b>0$ , then a possible value for the ratio $a/b$ , to the nearest integer, is:

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Tags: Algebra Geometry Probability

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