<p>In a table tennis tournament, every participant played every other participant exactly once. Although there were twice as many right-handed players as left-handed players, the number of games won by left-handed players was <img alt="$40\%$" height="14" src="https://latex.artofproblemsolving.com/f/4/e/f4e4e5c6d549ce47918b94180cad5c1644d9ea88.png" width="32" /> more than the number of games won by right-handed players. (There were no ties and no ambidextrous players.) What is the total number of games played?</p>

Question No: 357

In a table tennis tournament, every participant played every other participant exactly once. Although there were twice as many right-handed players as left-handed players, the number of games won by left-handed players was $40\%$ more than the number of games won by right-handed players. (There were no ties and no ambidextrous players.) What is the total number of games played?

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Tags: Algebra Combinatorics

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